/****模拟sqlserver中的dateadd函数*******
$part 类型：string
取值范围：year,month,day,hour,min,sec
表示：要增加的日期的哪个部分
$n 类型：数值
表示：要增加多少，根据$part决定增加哪个部分
可为负数
$datetime类型：timestamp
表示：增加的基数
返回 类型：timestamp
**************结束**************/
function dateadd($part,$n,$datetime){
$year=date("Y",$datetime);
$month=date("m",$datetime);
$day=date("d",$datetime);
$hour=date("H",$datetime);
$min=date("i",$datetime);
$sec=date("s",$datetime);
$part=strtolower($part);
$ret=0;
switch ($part) {
case "year":
$year+=$n;
break;
case "month":
$month+=$n;
break;
case "day":
$day+=$n;
break;
case "hour":
$hour+=$n;
break;
case "min":
$min+=$n;
break;
case "sec":
$sec+=$n;
break;
default:
return $ret;
break;
}
$ret=mktime($hour,$min,$sec,$month,$day,$year);
return $ret;
}

/****模拟sqlserver中的datediff函数*******
$part 类型：string
取值范围：year,month,day,hour,min,sec
表示：要增加的日期的哪个部分
$date1,$date2 类型：timestamp
表示：要比较的两个日期
返回 类型：数值
**************结束*(*************/
function datediff($part,$date1,$date2){
//$diff=$date2-$date1;
$year1=date("Y",$date1);
$year2=date("Y",$date2);
$month2=date("m",$date2);
$month1=date("m",$date1);
$day2=date("d",$date2);
$day1=date("d",$date1);
$hour2=date("d",$date2);
$hour1=date("d",$date1);
$min2=date("i",$date2);
$min1=date("i",$date1);
$sec2=date("s",$date2);
$sec1=date("s",$date1);

$part=strtolower($part);
$ret=0;
switch ($part) {
case "year":
$ret=$year2-$year1;
break;
case "month":
$ret=($year2-$year1)*12+$month2-$month1;
break;
case "day":
$ret=(mktime(0,0,0,$month2,$day2,$year2)-mktime(0,0,0,$month1,$day1,$year1))/(3600*24);
break;
case "hour":
$ret=(mktime($hour2,0,0,$month2,$day2,$year2)-mktime($hour1,0,0,$month1,$day1,$year1))/3600;
break;
case "min":
$ret=(mktime($hour2,$min2,0,$month2,$day2,$year2)-mktime($hour1,$min1,0,$month1,$day1,$year1))/60;
break;
case "sec":
$ret=$date2-$date1;
break;
default:
return $ret;
break;
}
return $ret;
}
?>